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4x^2-53x-112=0
a = 4; b = -53; c = -112;
Δ = b2-4ac
Δ = -532-4·4·(-112)
Δ = 4601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-53)-\sqrt{4601}}{2*4}=\frac{53-\sqrt{4601}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-53)+\sqrt{4601}}{2*4}=\frac{53+\sqrt{4601}}{8} $
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